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6b^2+12b+6=0
a = 6; b = 12; c = +6;
Δ = b2-4ac
Δ = 122-4·6·6
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$b=\frac{-b}{2a}=\frac{-12}{12}=-1$
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